prove that there is only one pair of (integer) perfect squares that differ by 53, and find it
prove that there is only one pair of (integer) perfect squares that differ by 53, and find it
Let's call the squares x2 and y2 so y2 – x2 = 53
Well, I couldn't figure out how to do it, so
I went to Desmos and plotted the curve of y = sqrt(x2 + 53)
and by careful scrutinization, discovered
the place where the curve crossed two
whole numbers on the grid. It wasn't
as hard as describing it sounds.
The answer is when x = 26 & y = 27 272 – 262 = 53
729 – 676 = 53
I can't prove that's the only pair. Sorry.
.