A line has a slope of $m,$ and its $y$-intercept is $(0,b)$. If $m = 8$ and $b = 14,$ then what is the $x$-intercept of the line?

kittykat Mar 4, 2024

#1**+1 **

equation of a line in standard form is: Ax + By + C = 0

x stands for x-intercept and y stands for y-intercept

the equation of a line in y-intercept form is y=mx+b

slope(m)= 8

y-intercept= (0,14)

Plugging this into the equation y=mx+b, we have:

y=8x+14 → change this into standard from by moving "y" to the other side

0=8x+y+14

substitute (0) for y to solve for x

0=8x+14

-14=8x

-14/8=x

**-7/4=x**

**therefore, the x-intercept of the line is -7/4**

hi1234 Mar 4, 2024

#1**+1 **

Best Answer

equation of a line in standard form is: Ax + By + C = 0

x stands for x-intercept and y stands for y-intercept

the equation of a line in y-intercept form is y=mx+b

slope(m)= 8

y-intercept= (0,14)

Plugging this into the equation y=mx+b, we have:

y=8x+14 → change this into standard from by moving "y" to the other side

0=8x+y+14

substitute (0) for y to solve for x

0=8x+14

-14=8x

-14/8=x

**-7/4=x**

**therefore, the x-intercept of the line is -7/4**

hi1234 Mar 4, 2024