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A line has a slope of $m,$ and its $y$-intercept is $(0,b)$. If $m = 8$ and $b = 14,$ then what is the $x$-intercept of the line?

 Mar 4, 2024

Best Answer 

 #1
avatar+39 
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equation of a line in standard form is:  Ax + By + C = 0
x stands for x-intercept and y stands for y-intercept
the equation of a line in y-intercept form is y=mx+b

slope(m)= 8
y-intercept= (0,14)
Plugging this into the equation y=mx+b, we have:

y=8x+14   → change this into standard from by moving "y" to the other side
0=8x+y+14

substitute (0) for y to solve for x

0=8x+14

-14=8x

-14/8=x

-7/4=x

therefore, the x-intercept of the line is -7/4

 Mar 4, 2024
 #1
avatar+39 
+1
Best Answer

equation of a line in standard form is:  Ax + By + C = 0
x stands for x-intercept and y stands for y-intercept
the equation of a line in y-intercept form is y=mx+b

slope(m)= 8
y-intercept= (0,14)
Plugging this into the equation y=mx+b, we have:

y=8x+14   → change this into standard from by moving "y" to the other side
0=8x+y+14

substitute (0) for y to solve for x

0=8x+14

-14=8x

-14/8=x

-7/4=x

therefore, the x-intercept of the line is -7/4

hi1234 Mar 4, 2024

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