+1439 A line has a slope of $m,$ and its $y$-intercept is $(0,b)$. If $m = 8$ and $b = 14,$ then what is the $x$-intercept of the line?
+39 equation of a line in standard form is: Ax + By + C = 0
x stands for x-intercept and y stands for y-intercept
the equation of a line in y-intercept form is y=mx+b
slope(m)= 8
y-intercept= (0,14)
Plugging this into the equation y=mx+b, we have:
y=8x+14 → change this into standard from by moving "y" to the other side
0=8x+y+14
substitute (0) for y to solve for x
0=8x+14
-14=8x
-14/8=x
-7/4=x
therefore, the x-intercept of the line is -7/4
+39 equation of a line in standard form is: Ax + By + C = 0
x stands for x-intercept and y stands for y-intercept
the equation of a line in y-intercept form is y=mx+b
slope(m)= 8
y-intercept= (0,14)
Plugging this into the equation y=mx+b, we have:
y=8x+14 → change this into standard from by moving "y" to the other side
0=8x+y+14
substitute (0) for y to solve for x
0=8x+14
-14=8x
-14/8=x
-7/4=x
therefore, the x-intercept of the line is -7/4
