it's basically "what's the probability that at least 2 don't roll to be 1?"
So the probability of getting 2 1s is (1/6)^2 and then 1 is total probability so we subtract.
Thus, 1 - 1/36
BUT i think we need to do casework
You see, we have the ones where there's 0 ones, 1 one, ...
then you have to add those too?
idk