hugomimihu

Again. I can not see your numbers.

So 300 / 360 = 5/6. The arc thus is 1/6 of the circumference.

The circumference is 8^2 π = 64π. 1/6 of that is 64π/6 = 32π/3.

If you don't understand anything feel free to ask!

Please fix your latex, and add the image.

What's the constant term of the expansion of (do + not + cheat + on + your) * (A*o*P*S + Homework) ?

Why do I have a feeling you are to same person saying this every time? * nervous laugh*

LOL

Take care, stay safe.

The largest integer less than 10000 is 8888, since each digit is the largest even.

8 * 4= 32, which isn't divisible by 9.

All multiples of 9 equal or less than 32:

9

18

27

We can't get 9 or 27 since those are odd and we can only subtract two(to get the next largest even)

So 32 - 18 = 14, so we have14/2 = 7. So we can only subtract 8/2 = 4 sets of 2's from the ones digit, so that's 8880.7-4 is 3 so we subtract 3*2 = 6 from the tens so 8820.

8+8+2 = 18

If you don't understand anythign feel free to ask!

A number x to the negative power, say -y, is 1 / (x^y), so we have 1/ (5^3) = 1 / 125

If you don't understand anything feel free to ask!

The S.A. of a cylinder is 2(πr^2) + h* 2πr, so we have 2πr^2 + 4πr^2 = 6πr^2.

The area of the 2 bases is 2(πr^2) so 2/6 = 1/3.

If you don't understand anything feel free to ask! :)

Plugging it in to the quadratic formula

\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)

We have.

\(x = {10 \pm \sqrt{-10^2-4*9} \over 2} = {10 \pm \sqrt{64}\over 2} = {10 \pm 8}\over2\)

So 10 +/- 8  OVER 2 is  18/2 or 1. 

Plugging into the equation

9^2 - 90 +9 = 0 = 81 + 9 - 90 = 0

YUP!

1^2 - 10 + 9 = 0 = 1 + 9 - 10 = 10-10 = 0.

YUP!

Great those are our roots.

A quadratic can only have two,

If you don't understand anything feel free to ask!