Interesting enough... No wonder it burnt your brain, here we go:
Illustration (Made om quick session in 3 mins)
We know the height of the building is 33 meters, therefore we obtain the following equation:
Set the distance from the foundation of the building to the church's foundation \(A\).\
Apply trigonometric identity.
The angle of depression is 25 degrees, therefore:
\(A=tan(25°)*33\)
\(A≈ 0.4663*25\)
\(A≈ 11.6575\)
That means the distance from the church's top to the same height of the building is also \(A=11.6575\)
Applying trigonometric identites for the second time
Church height=\(11.6575*sec(18°)\)
\(≈11.6575*1.0515\)
\(=12.258\)=Church's Height
Q.E.D.
(Don't even ask me about how tensed I am to win over Heureka over the speed of solving this question)