+178 Long story short, was doing a derivative worksheet given by my teacher, got a killstreak for sixty-seven questions and got stuck at No.68, now I'm pleasing for some help on a math forum to solve this so anything bad won't happen in class:
(Neither sum rule, difference rule, product rule, quotient rule, or power rule worked for me.)
ddx[tan5(ln(3x2+3)+8x)]
Please I'm begging you.
(This question will probably get lost in the forum section anyways.)
Differentiate the sum term by term and factor out constants:
= 8 d/dx(x) + d/dx(log(3 + 3 x^2)) 5 sec^2(8 x + log(3 + 3 x^2)) tan^4(8 x + log(3 + 3 x^2))
The derivative of x is 1:
= 5 sec^2(8 x + log(3 + 3 x^2)) (d/dx(log(3 + 3 x^2)) + 1 8) tan^4(8 x + log(3 + 3 x^2))
Using the chain rule, d/dx(log(3 x^2 + 3)) = ( dlog(u))/( du) ( du)/( dx), where u = 3 x^2 + 3 and ( d)/( du)(log(u)) = 1/u:
= 5 sec^2(8 x + log(3 + 3 x^2)) (8 + (d/dx(3 + 3 x^2))/(3 x^2 + 3)) tan^4(8 x + log(3 + 3 x^2))
Differentiate the sum term by term and factor out constants:
= 5 sec^2(8 x + log(3 + 3 x^2)) (8 + d/dx(3) + 3 d/dx(x^2)/(3 x^2 + 3)) tan^4(8 x + log(3 + 3 x^2))
The derivative of 3 is zero:
= 5 sec^2(8 x + log(3 + 3 x^2)) (8 + (3 (d/dx(x^2)) + 0)/(3 + 3 x^2)) tan^4(8 x + log(3 + 3 x^2))
Simplify the expression:
= 5 (8 + (3 (d/dx(x^2)))/(3 + 3 x^2)) sec^2(8 x + log(3 + 3 x^2)) tan^4(8 x + log(3 + 3 x^2))
Use the power rule, d/dx(x^n) = n x^(n - 1), where n = 2: d/dx(x^2) = 2 x:
= 5 sec^2(8 x + log(3 + 3 x^2)) (8 + 2 x 3/(3 + 3 x^2)) tan^4(8 x + log(3 + 3 x^2))
Simplify the expression:
Answer: | = 5 (8 + (6 x)/(3 + 3 x^2)) sec^2(8 x + log(3 + 3 x^2)) tan^4(8 x + log(3 + 3 x^2))
