how far did a person fall if they fell for 3 minutes and 22 seconds

Assuming the gravitational acceleration is $9.8m/s^2$ in your question.

3 minutes and 22 seconds = 202 seconds

The distance fallen is proportional to one half the square of time times the acceleration:

$Δx=\frac{1}{2}at^2$

Plug $a=9.8m/s^2$ and $t=202 s$

$Δx=\frac{1}{2}9.8\left(202\right)^2$

$=4.9(40804)$

$=199939.6 m ≈ 200 km$

(Fun fact: You can fall for over 12 minutes from the solar system's highest cliff- The Verona Rupes on Miranda)

But you can never assume you need to know the vlocity and the rate of witch you are falling