+178 Assuming the gravitational acceleration is \(9.8m/s^2\) in your question.
3 minutes and 22 seconds = 202 seconds
The distance fallen is proportional to one half the square of time times the acceleration:
\(Δx=\frac{1}{2}at^2\)
Plug \(a=9.8m/s^2\) and \(t=202 s\)
\(Δx=\frac{1}{2}9.8\left(202\right)^2\)
\(=4.9(40804)\)
\(=199939.6 m ≈ 200 km\)
(Fun fact: You can fall for over 12 minutes from the solar system's highest cliff- The Verona Rupes on Miranda)
+2 But you can never assume you need to know the vlocity and the rate of witch you are falling
