juriemagic

Thanks Alan, will check it out..

Thank you Melody...I'm sure it must have been a pelling error. .....spelling error...lol....Stay well untill next time!

Hello sweet Melody!!!..

oops, won't say that again..., but I WANTED to....

The 1st sequence is Fibonacci yes, I googled on that but there does not seem to be a mathematical layterm solution for it, 

The 2nd sequence is a problem,

T1 = n,

T2 = n^2

T3 = (n+1)^2

T4 = (n+1)^2

T5 = n^2

So, I cannot determine a nth term rule....say, for the 10th term?

The 3rd sequence I've got sorted....thank you sooo much for assisting...

Hi guest,

i do appreciate your response, however my problem really is how to calculate for example the 10th term for each of these sequences. I struggle to put together a formula..

The 3rd sequence I gave, i finnaly got...it's just Tn = n^3

Hi Daewei,

yes I fully understand this now...thank you for your input...

Hi Melody,

I always thought that after a log, everything following is part of that log function....I have learnt now that only the immediate value following the log, is applicable to the log function, and all other terms really stand "loose' from that function...Thank you very much for teaching me something again today....I really do appreciate...

Thanks for this...but this confuses me...why is it mathematically incorrect to do the sum the way I did..which gives x to be 28..then add 2??

Isee,

however I did a test..

if i substitute x with 3, which gives us 2 log5 = log900, then things do not balance since 2 log 5 equates to 1,397, while log 900 equates to 2.954. However, with x being 28, the equation becomes 2 log30, which is the same as log 900..this is confusing?

hi guys,

i do appreciate the answers. So, is doing this then wrong?

\(2logx+2=log900\)

\(log(x+2)^2=log900\)

\((x+2)^2=900 \)

\(x+2= \sqrt900\)

\(x+2= \pm30\)

\(x=28\)

or

\(x=-32\) which is not applicable

so \(x=28\)

WOW!!!...great way of solving this!!!..Tank you very very much!!