Alan, Thanx for walking me through this...honestly, you will never realise how much this means!!..okay, x:y = 3:2
that gives \(2x=3y\)
which can go to \(2x-3y=0\)
Nothing can be factored..soooo, mabe then I should look at simultaneous equations???, meaning...
\(2x-3y=0.....(1)\)
\(x+y=2\)
\(x=2-y.....(2)\)
(2) in (1)
\(2(2-y)-3y=0\)
\(4-2y-3y=0\)
\(-5y=-4\)
\(y= {4 \over 5}...(3)\)
(3) in (2)
\(x=2- {4 \over5}\)
\(x={6 \over5}\)
So x then is 6\5 and y is 4\5
Is this correct maybe??..
..This is for a grade 6 learner...My reason for asking assistance is because of the fact that this learner has not yet in his curriculum
..but..I will check it and I hereby also say a BIIIG thank you!..
