My guy I gave u like 10 just today LOL (u deserve it :D)
Really LOL!
Yo CentLord I just got mastered in every alcumus topic week 1-7 YAY!
Ok Heres what I would do:
So the probability that all will show a 1 is \((1/6)^5.\)
The probability that at most 4 will show one = \(1 - (1/6)^5 \)
\((6^5 - 1) / 6^5 =\)
\(7775 / 7776\)
I think week 6 or 7
Like 2013 I think...
While that comment made me laugh, it's kinda rude and Hugo's intentions are good. So next time don't be so rude Ok!
idk lol i guess that was kinda random but what i'm saying is that my answers r bad and his r good
See here - "https://web2.0calc.com/questions/pls-pls-help"
Thumbs up for not giving away a solution
+639 
