+636 Wu rolls two fair, six-sided dice. You are not told what the rolls were, but you are told that the sum of the two rolls is a prime. What is the probability that the sum of the two rolls is 5
The possible rolls are (1,4), (2,3), (3,2), (4,1), so the probability is 4/36 = 1/9.
+23246 The sum could be either a 3, a 5, a 7, or an 11.
3 = (1,2) or (2,1)
5 = (1,4), (4,1), (2,3) or (3,2)
7 = (1,6), (6,1), (2,5), (5,2), (3,4), or (4,3)
11 = (5,6) or (6,5)
There are 14 winning possibilities out of a possible 36 possibilities: 14/36 = 7/18
+738 Hi LuckyDucky!
I'm probably wrong too, but I'll give this problem a shot too :)
So I basically did the same thing as the Guest who answered your question, but I think the answer is actually \(\boxed{\frac{4}{15}}\)because the questions says "you are told that the sum of the two rolls is a prime" the answer is actually 4 out of the prime sums, and there are 15 possible prime sums. (The Guest made the mistake of making it out of all 36 possible sums)
So, I think the answer is \(\boxed{\frac{4}{15}}\)
I'm probably wrong, but I hope this helped you anyway
:)
