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# HELPPPPP

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Compute 5^0 + 3^-2 + (9/8)^-1

By the way, 9/8 is a fraction to the -1th

Help is apprenticed because this is due very soon

:D

Apr 29, 2020
edited by LuckyDucky  Apr 30, 2020

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Ight, Imma try this :D

50 is simply 1

$$3^{-2} = \frac{1}{3^2} = \frac{1}{9}$$'

$$(\frac{9}{8})^{-1} = \frac{8}{9}$$

So 1 + 1/9 + 8/9 = 2 :D

Apr 29, 2020

#1
+299
+3

Ight, Imma try this :D

50 is simply 1

$$3^{-2} = \frac{1}{3^2} = \frac{1}{9}$$'

$$(\frac{9}{8})^{-1} = \frac{8}{9}$$

So 1 + 1/9 + 8/9 = 2 :D

CentsLord Apr 29, 2020
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Yesssss Thank you so much it is correct 100/100

Thank you so much for explaining the question VERY CLEARLY and for your time

:D

LuckyDucky  Apr 29, 2020
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You're Welcome (:

CentsLord  Apr 30, 2020
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Luckyduck,

If you want to write  $$(\frac{9}{8})^{-1}$$    you need brackets.    (9/8)^-1

.
Apr 30, 2020
edited by Melody  Apr 30, 2020
edited by Melody  Apr 30, 2020
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Oh, thanks, Melody!

I will use that in the future!

:D

LuckyDucky  Apr 30, 2020
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Better?

LuckyDucky  Apr 30, 2020