+639 Compute 5^0 + 3^-2 + (9/8)^-1
By the way, 9/8 is a fraction to the -1th
Help is apprenticed because this is due very soon
:D
+771 Ight, Imma try this :D
50 is simply 1
\(3^{-2} = \frac{1}{3^2} = \frac{1}{9} \)'
\((\frac{9}{8})^{-1} = \frac{8}{9}\)
So 1 + 1/9 + 8/9 = 2 :D
+639 Yesssss Thank you so much it is correct 100/100
Thank you so much for explaining the question VERY CLEARLY and for your time
:D
