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Compute 5^0 + 3^-2 + (9/8)^-1

 

By the way, 9/8 is a fraction to the -1th

 

Help is apprenticed because this is due very soon

 

:D

 Apr 29, 2020
edited by LuckyDucky  Apr 30, 2020

Best Answer 

 #1
avatar+299 
+3

Ight, Imma try this :D

 

50 is simply 1

\(3^{-2} = \frac{1}{3^2} = \frac{1}{9} \)'

\((\frac{9}{8})^{-1} = \frac{8}{9}\)

So 1 + 1/9 + 8/9 = 2 :D

 Apr 29, 2020
 #1
avatar+299 
+3
Best Answer

Ight, Imma try this :D

 

50 is simply 1

\(3^{-2} = \frac{1}{3^2} = \frac{1}{9} \)'

\((\frac{9}{8})^{-1} = \frac{8}{9}\)

So 1 + 1/9 + 8/9 = 2 :D

CentsLord Apr 29, 2020
 #2
avatar+656 
+2

Yesssss Thank you so much it is correct 100/100

Thank you so much for explaining the question VERY CLEARLY and for your time

 

:D

LuckyDucky  Apr 29, 2020
 #3
avatar+299 
+1

You're Welcome (:

CentsLord  Apr 30, 2020
 #4
avatar+109484 
+2

Nicely answered CentsLord    laugh

 

Luckyduck,

 

If you want to write  \((\frac{9}{8})^{-1}\)    you need brackets.    (9/8)^-1

.
 Apr 30, 2020
edited by Melody  Apr 30, 2020
edited by Melody  Apr 30, 2020
 #5
avatar+656 
+1

Oh, thanks, Melody!

I will use that in the future!

:D

LuckyDucky  Apr 30, 2020
 #6
avatar+656 
+1

Better?

LuckyDucky  Apr 30, 2020

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