+636 If \($\left(\frac{1}{3}\right)^{-2}=27^x$\) what is the value of x? Express your answer as a common fraction.
Thanks everyone!
+128474 (1/3)^(-2) = 27^x
Get the bases equal......
(3^(-1))^(-2) = ( 3^3 )^x
3^2 = 3^(3x)
We have the bases equal...solve for the exponents....
2 = 3x
x =2/3
+636 Yup! that's 100% correct
Also, next time I know how to do it because of your explanation
