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If  $$\left(\frac{1}{3}\right)^{-2}=27^x$$ what is the value of x? Express your answer as a common fraction.

Thanks everyone!

May 1, 2020

#1
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(1/3)^(-2)  =  27^x

Get the bases equal......

(3^(-1))^(-2)  = ( 3^3 )^x

3^2  = 3^(3x)

We have the bases equal...solve for the exponents....

2 = 3x

x =2/3

May 1, 2020
#2
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Yup! that's 100% correct

Also, next time I know how to do it because of your explanation

LuckyDucky  May 1, 2020
#3
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hes right man  hes smart

grannygod123  May 1, 2020
#4
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Lol!

LuckyDucky  May 1, 2020