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If  \($\left(\frac{1}{3}\right)^{-2}=27^x$\) what is the value of x? Express your answer as a common fraction.

 

Thanks everyone!

 May 1, 2020
 #1
avatar+111329 
+2

(1/3)^(-2)  =  27^x

 

Get the bases equal......

 

(3^(-1))^(-2)  = ( 3^3 )^x

 

3^2  = 3^(3x)

 

We have the bases equal...solve for the exponents....

 

2 = 3x

 

x =2/3

 

 

cool cool cool

 May 1, 2020
 #2
avatar+657 
+2

Yup! that's 100% correct

Also, next time I know how to do it because of your explanation

 

coolsmileycool

LuckyDucky  May 1, 2020
 #3
avatar+116 
+1

hes right man cool hes smart

grannygod123  May 1, 2020
 #4
avatar+657 
+2

Lol!

LuckyDucky  May 1, 2020

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