MathProblemSolver101

Here is one I made a while ago...

from tkinter import *

def iCalc(source, side):

storeObj = Frame(source, borderwidth=4, bd=4, bg="powder blue")

storeObj.pack(side=side, expand =YES, fill =BOTH)

return storeObj

def button(source, side, text, command=None):

storeObj = Button(source, text=text, command=command)

storeObj.pack(side=side, expand = YES, fill=BOTH)

return storeObj

class app(Frame):

def __init__(self):

Frame.__init__(self)

self.option_add('*Font', 'arial 20 bold')

self.pack(expand = YES, fill =BOTH)

self.master.title('Calculator')

display = StringVar()

Entry(self, relief=RIDGE, textvariable=display,

justify='right'

, bd=30, bg="powder blue").pack(side=TOP,

expand=YES, fill=BOTH)

for clearButton in (["C"]):

erase = iCalc(self, TOP)

for ichar in clearButton:

button(erase, LEFT, ichar, lambda

storeObj=display, q=ichar: storeObj.set(''))

for numButton in ("789/", "456*", "123-", "0.+"):

FunctionNum = iCalc(self, TOP)

for iEquals in numButton:

button(FunctionNum, LEFT, iEquals, lambda

storeObj=display, q=iEquals: storeObj

.set(storeObj.get() + q))

EqualButton = iCalc(self, TOP)

for iEquals in "=":

if iEquals == '=':

btniEquals = button(EqualButton, LEFT, iEquals)

btniEquals.bind(' ', lambda e,s=self,

storeObj=display: s.calc(storeObj), '+')

else:

btniEquals = button(EqualButton, LEFT, iEquals,

lambda storeObj=display, s=' %s ' % iEquals: storeObj.set

(storeObj.get() + s))

def calc(self, display):

try:

display.set(eval(display.get()))

except:

display.set("ERROR")

if __name__=='__main__':

app().mainloop()

Let's first expand $4(x+3):$ we have $4 \cdot x + 4 \cdot 3 = 4x + 12.$

Now, we have to subtract: $6-(4x+12) = 6-4x-12 = (6-12) - 4x = \boxed{-6 - 4x}$

The best way to learn is by experience. If you make mistakes, it's OK. Given that, can you take a shot at this: $4+3(x+2)$?

 - Jimmy

Diagram, please? I am a visual learner so it is improbable for me to solve a geometrical problem without a diagram.

 - Jimmy

Thank you so much! I've been doing some math and equations but always ended up with a contradictory statement... and so was stuck on this for quite a while. I really appreciate your help, as I am, relatively abysmal in number theory compared to you.

 Jimmy

A 100-foot rope is cut into three pieces. The first piece is three times as long as the second, and the third piece is 30 feet shorter than the second. How many feet long is the shortest piece?

Let First Piece = $p_1$

Let Second Piece = $p_2$

Let Third Piece = $p_3$

$p_1 + p_2 + p_3 = 100$

$p_1 = 3p_2$

$p_3 = p_2 - 30$

$3p_2 + p_2 + p_2 - 30 = 100$

$5p_2 = 130$

$p_2 = 26$

$p_1 = 78$

$p_3 = -4$

Where did I go wrong???

$(\frac{2}{5},8) = (\frac{2}{5},8)$

Lowest point: $0.4$

Time of lowest point: 8:00 PM

General Equation of Parabola: $y=a(x-h)^2 + k$ where $(h,k)$ is the vertex of the parabola.

We have $y=a(x-4)^2 + 0$

We can’t the vertex $(4,0)$ again to plug in for $(x,y)$ because it will yield: $0=0+0.$

Let’s use the other point given(namely $(6,2)$): $2=a(6-4)^2 + 0$

We have $a=\frac{2}{4}=\frac{1}{2}.$

Thus the equation is $y=\frac{1}{2}(x-4)^2$

$\sin(90)=1$

$\sin(-90)=-1$

$\sin(270)=-1$

$\sin(-270)=1$

Apparently, $\sin(-n) = - \sin(n)$

2 integers have a sum of 6, and a product of -72. What are the numbers?

$a+b=6$

$ab=-72$

$a=6-b$

$6b - b^2 = -72$

$b^2 - 6b - 72 = 0$

$(b-12)(b+6)=0$

iff $b=12, a=-6$

iff $b=-6, a=12$

$\boxed{-6, 12}$

$\lfloor{\frac{187}{4}}\rfloor=\lfloor{46.75}\rfloor=\boxed{46}$