Given $x + \frac{1}{x} = k,$ find a formula with $k$ for $x^n + \frac{1}{x}^n$
I am not sure what kind of answer you are looking for
I expanded \((x+\frac{1}{x})^n\)
and got
\(x^n+\frac{1}{x^n}=k^n-\displaystyle \sum_{r=1}^{n-1}\binom{n}{r} x^{n-2r}\)
+876 
