Nacirema

Message me if you need any more help.👌

instead of , which caused

Missing numbers. Please revise the question.

Sorry, had to eat dinner.

... And how did you know I was refering to AoPS. Whatever, irrelevent. 

Here is why I did that.

So, if we took the probability that the red is first, then it is 4/15. Because there is no replacement, we have to remove one value from both numerator and denominator: (4-1)/(15-1). One mpre time for the third: (4-2)/(15-2). Then we multiply them all together. Careful: if you subtract 1/1 instead of 1 from the numerator and 1 from the denominator, then you will get a wrong number. 

This in mind, tell me how I did the other 2 parts: white and blue. Just reply to this thread.

Lol, I never gave the answer. 

Here is the answer: 

\((\frac {4}{15} \cdot \frac {3}{14} \cdot \frac {2}{13})+(\frac {5}{15}\cdot\frac {4}{14}\cdot\frac {3}{13}) + (\frac {6}{15}\cdot \frac {5}{14}\cdot \frac {4}{13})\)

Compute it using any calculator. Don't expect us to do that as well. (Next time, use the class message board.)

Lol, true. (Nauseated be like: YA THINK?)

Hi, I'm good. Sorry to hard you got hurt. What is the math problem lol?

There are three cases, all are red, all are white and all are blue. 

The total marbles (NOT PROBABILITY) is 15. Next time, look at the transcript or actually pay attention in class.

Thank you all who helped! (jugoslav, I did not ask for the answer, I wanted to do it on my own ... but, honestly, thx.)

Hi! It is sad seeing such old members leave and never come back like Rom and Nauseated. :( I am glad, as many of the other users may as well, that at least you came back to say a polite goodbye. You will be missed on the forum.