nerdiest

look at builderboi's answer, not mine

\(https://web2.0calc.com/questions/counting-and-probability_7\)

Thank you all for your answers, I was kinda stumped when I reached CPhill's answer, and it was wrong.

TYSM

here

By symmetry, \(\widehat{BD}=\widehat{CA}=100^\circ\). Furthermore,\(\widehat{AB}=\widehat{CD}\) , so\([360^\circ=\widehat{AB}+\widehat{BD}+\widehat{DC}+\widehat{CA}=2\widehat{AB}+200^\circ\)Therefore the arc \(\widehat{AB}\) measures \(80^\circ\). Since the diameter of the circle is \(36''\), the length of the arc is \(\frac{80}{360}(\pi\cdot36)=\boxed{8\pi}\text{~inches}.\)

Welp, I guess both of you agree!

I drew one line down from b to d to make a 90 degree angle.

90+50=140

180-140=40^o

and that was CPhill's way, but it was wrong...

ya

he

he

he

Melody,

I think you have done this question before... :)

https://web2.0calc.com/questions/if-where-represents-a-base-8-digit-and-represents

If I understand your question:
This is the "closed form" of each term:
a_n = 1/2 (6 n + (-1)^(n + 1) + 13). 
And the number 235236(n) is a multiple of 7 in the following bases:
n = 10, 12, 16, 18, 22, 24, 28, 30, 34, 36, 40, 42, 46, 48, 52, 54, 58, 60, 64, 66, 70, 72, 76, 78, 82, 84, 88, 90, 94, 96, 100.

guest. 

why did you just downvote all of my answers when they were right?

:(