+0  
 
0
34
6
avatar

Bob and Meena play a two-person game which is won by the first person to accumulate 10 points. At each turn Bob gains a point with probability of 1/3. If he doesn't get a point, then Meena gets a point. Meena is now ahead 9 to 8. What is the probability that Meena will win? Express your answer as a common fraction.

 Jul 28, 2022
 #1
avatar+1118 
+3

look at builderboi's answer, not mine

\(https://web2.0calc.com/questions/counting-and-probability_7\)

 Jul 28, 2022
 #2
avatar
+1

Can you format it a little better? I tried typing the url and it didn't give me builderboi's answer. I was sure I didn't mistype it! To be sure you can reupload it please so I can copy and paste, in regular text so I can

Guest Jul 28, 2022
 #4
avatar+2321 
0

https://web2.0calc.com/questions/counting-and-probability_7

BuilderBoi  Jul 28, 2022
 #6
avatar+1118 
+3

sry

 

the website url wasn't working, so i just pasted in LATEX, my bad

nerdiest  Jul 28, 2022
 #3
avatar
-3

The only way Meena loses is if Bob wins the next 2 points. The probability of Bob winning the next 2 points is (1/3)^2  = 1/9.

 

So, the probability Meena wins is 1 - 1/9 = 8/9. 

 Jul 28, 2022
 #5
avatar+2321 
0

That was my answer

BuilderBoi  Jul 28, 2022

13 Online Users