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# Bob and Meena.

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Bob and Meena play a two-person game which is won by the first person to accumulate 10 points. At each turn Bob gains a point with probability of 1/3. If he doesn't get a point, then Meena gets a point. Meena is now ahead 9 to 8. What is the probability that Meena will win? Express your answer as a common fraction.

Jul 28, 2022

### 6+0 Answers

#1
+1162
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look at builderboi's answer, not mine

\(https://web2.0calc.com/questions/counting-and-probability_7\)

Jul 28, 2022
#2
+1

Can you format it a little better? I tried typing the url and it didn't give me builderboi's answer. I was sure I didn't mistype it! To be sure you can reupload it please so I can copy and paste, in regular text so I can

Guest Jul 28, 2022
#4
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https://web2.0calc.com/questions/counting-and-probability_7

BuilderBoi  Jul 28, 2022
#6
+1162
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sry

the website url wasn't working, so i just pasted in LATEX, my bad

nerdiest  Jul 28, 2022
#3
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The only way Meena loses is if Bob wins the next 2 points. The probability of Bob winning the next 2 points is (1/3)^2  = 1/9.

So, the probability Meena wins is 1 - 1/9 = 8/9.

Jul 28, 2022
#5
+2667
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That was my answer

BuilderBoi  Jul 28, 2022