NinjaDevo

Wow! That actually helped alot!

Thanks Melody. :)

Thanks anonymous.

If we're not carefull, be can just solve equations like these in a breeze.

Thanks for the correction, I didn't even think about that.

We just need to make this into a triangle, then knowing that it is a right triangle and knowing the length/height we can use the Pythagorean Theorem to solve for the distance.

To find c we can use the Pythagorean Theorem (a^2 + b^2 = c^2)

a^2 + b^2 = c^2

3^2 + 6^2 = c^2

9+36=c^2

45=c^2

√45 = c

c = √45

or

c ≈ 6.7

You take a logging company and throw a bunch of angry protesters at it!

I'm sure someone will give you a proper answer. :)

So we are looking to get x = something. The key thing to remember here is that whatever you do to one side of the equation, you have to do the same thing to the other side.

So if I want to subtract 2 from one side, I can do that but I have to subtract 2 from the other side too.

3x-5=2x+8            ---Let's subtract 2x from both sides. We can do this because we are doing it to both sides

-2x    -2x

--------------

x-5=8                 ---Now let's add 5 to both sides

x = 13

And there we go!

To check this, we can put 13 in where there's an x in the original equation. If we did it right, we'll get a true statement, like 3=3, or 6=6.

3x-5=2x+8          ---Put 13 in for x

3(13)-5=2(13)+8

39-5=26+8

34=34

This is a true statement, so we solved it correctly.

That's a pretty nice puzzle anonymous. Had me stumped for a little bit.

x^2+50-5x=10x

x^2+50-15x=0

x^2-15x+50=0

(x-10)(x-5)=0

(x-10)=0 | (x-5)=0

x-10=0 | x-5 = 0

x = 10 | x = 5

Thanks guys.

I wouldn't say that I could handle this forum by myself though. You guys do alot around here!

I think this is what you mean:

To solve this, we can use the rule:

So now we have:

So our answer is a⁶

Are you wondering how many place values are in 486!

or are you wondering how many number 0's are in 486!?

I'm not sure if there is a formula to figure this out. I'm sure someone else will post an answer if there is.