pro35hp

Hello Melody,

your steps are perfectly done.

there is a little mistake you've done 

\(\frac {200\times 25\; + \;5\times 800}{ 5 \times 20 \;+\; 25 \times 4 }\\ \)

you did 200*2+5*800

but the tutorial is nicely done.

the real answer to his problem btw is 45

as well as you can do factoring if you want 

because you didn't explain what do you want

you can factor it by 2

so 2(x+3*2xy-y)=2(x+6xy-y)

\(\sqrt[1/5]{3} = 3^{\frac{1}{\frac{1}{5}}} = 3^5 , \)Am I right?

I don't have any thought , do you have any hint , 'cause you said you realized it is easy 

it works just like equations

but if you multiply by -1 or negative number , it inverses

so you just need to subtract 15

15+n<25

n<10

so all solutions for this inequality are under 10 

the biggest integer who satisfy this equation is 9 

just solve it like equations rule

but don't forget when you are multiplying by negative number

or squaring negative numbers

4+4+4+4=4*4=16

\(( \frac{27}{64})^{- \frac{4}{3}} = ( \frac{27*27^{1/3}}{64*64^{1/3}})^{-1} = ( \frac{27*3}{64*4} )^{-1}= \frac{256}{81}\)

Subtract 12 from each side

will get \(\sin \left(2x\right)+2\left(2\cos \left(x\right)-3\sin \left(x\right)\right)-12=0\)

Use the identity \(\sin \left(2x\right)=2\cos \left(x\right)\sin \left(x\right)\)

\(\left(2\cos \left(x\right)-3\sin \left(x\right)\right)2+2\cos \left(x\right)\sin \left(x\right)-12=0\)

\(2\left(2\cos \left(x\right)+\cos \left(x\right)\sin \left(x\right)-3\sin \left(x\right)-6\right)\)

\(=2\left(\sin \left(x\right)+2\right)\left(\cos \left(x\right)-3\right)\)

solving each part equivalent to 0

\(\sin \left(x\right)+2=0\:\:\:\mathrm{or}\:\:\:\cos \left(x\right)-3=0\)

sinx cannot be -2

and cos x cannot be 3 

hence , no answer in R

Hello Max,

you may find this interesting to read

Thanks Melody

\(x^{8+y}+x^9+x^{10+z} = x^8(x^y+x+x^{z+2}) \)

I really can't edit it , connection problems or website problem , I don't know either

that's why I made a reply instead of editing