+0  
 
+5
692
8
avatar

How to factor the exponents with variables?
For example x with exponent 8 but the exponent is with variables.
 

 Jul 12, 2016

Best Answer 

 #6
avatar+136 
+5

\(x^{8+y}+x^9+x^{10+z} = x^8(x^y+x+x^{z+2}) \)

.
 Jul 12, 2016
 #1
avatar+118608 
+1

Not sure what you mean

 

\(x^8+5x^6\\ x^6*x^2+x^6*5\\ =x^6(x^2+5)\)

 

 

does that help ??

 Jul 12, 2016
 #6
avatar+136 
+5
Best Answer

\(x^{8+y}+x^9+x^{10+z} = x^8(x^y+x+x^{z+2}) \)

pro35hp  Jul 12, 2016
 #4
avatar+118608 
0

Could you present you last answer properly in LaTex please pro35hp?  

It is correct :)

 Jul 12, 2016
 #5
avatar+136 
0

I really can't edit it , connection problems or website problem , I don't know either

that's why I made a reply instead of editing crying

 Jul 12, 2016
 #8
avatar+118608 
+5

I can't edit either.

Not many people can I don't know why.

I wanted you to do exactly as you have done.

I have deleted your earlier post to try and limit confusion :)

 Jul 12, 2016

4 Online Users

avatar
avatar
avatar
avatar