The original expression is:
\(\sqrt{2} + \sqrt{3} + {1\over2\sqrt{2} + 3\sqrt{3}}\)
Next we can simplify the fraction part of the expression by multiplying the denominator by the difference of squares;
The expression is now:
\(\sqrt{2}+\sqrt{3} + {3\sqrt{3}-2\sqrt{2}\over19}\)
Then we can multiply the first two terms of the expression by \(19\) to get:
\({19\sqrt{2}\over19} + {19\sqrt{3}\over19} + {3\sqrt{3}-2\sqrt{2}\over19}\)
Then adding up the numerators and simplifying we get:
\(17\sqrt{2} + 22\sqrt{3}\over19\)
Thus, \(a\), \(b\), and \(c\) are \(17\), \(22\), and \(19\) respectively.
Since we are looking for the sum of our three "variables", we add \(17+22+19\) to get:
\(58\), which is the answer.
:D