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# easy trig/precalc question help please

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How many values of $$x$$ with $$0^\circ\le x < 990^\circ$$ satisfy $$\sin x = -0.31$$?

Thanks for any help given!

Jan 31, 2022

#1
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Hello proyaop!

$$\frac{900^o}{360^o}=2.5\ \to 2\cdot 2=\color{blue}4$$

proyaop, the negative sine values are in the third and fourth quadrants!

4 values satisfy sin x = -0.31.

!

Jan 31, 2022
edited by asinus  Jan 31, 2022
#2
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It was 5 :(

thanks asinus and thx for the reminder melody :D

proyaop  Jan 31, 2022
edited by proyaop  Jan 31, 2022
#3
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Don't be rude Proyaop, it gets you nowhere.

Besides I think you are better than that.

When someone tries to help you, you say thank you! (And you do not take points off them!)

Do you still want help?  You didn't state, one way or the other.

Melody  Jan 31, 2022
edited by Melody  Jan 31, 2022