what is 4/3 to the third power?
\({4\over 3}^3 = {4\over 3}\times {4\over 3}\times {4\over 3} = {64\over 9} = \color{brown}\boxed{7 {1\over9}}\)
Actually \(({4\over3})^3\) is \(4^3\over3^3\), that simplifies to \(64\over27\).
Thus the correct answer to this problem is \(64/27\).
Hint: 64/27 = 2 10/27
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