rarinstraw1195

Cube root the numerator and the denominator.

Cube root of 8 is 2

Cube root of 27 is 3

The cube root of 8/27 is 2/3

You are correct, madam. It it horrible to impersonate anyone, let alone a moderator! We must slay this impostor at once!

Do you mean h^5 or 5h?

If h^5, then it is h^5+i

If 5h, then it is 5h+i

2.1*4+3.5*2^2

2.1*4+3.5*4

8.4+14

22.4

:)

\({y \over4} = {x \over 3}\)

x+y=21

Mutiply by 3 on both sides. 

\(x = {3y \over4}\)

and x+y=21

So, substitute \({3y \over4}\)

for x.

So, then y+3y/4=21

Multiply all terms by 4.

4y+3y=84

7y=84

Divide by 7.

y=12

Madam(I know), thank you for calming down, I thought you might burst a vessel! 

y+z+9+6=y+z+15

A: Water.

Q: Poor people have it. Rich people need it. If you eat it you die. What is it?
 

Q: Mary’s father has 5 daughters – Nana, Nene, Nini, Nono. What is the fifth daughters name?

Q: A dad and his son were riding their bikes and crashed. Two ambulances came and took them to different hospitals. The man’s son was in the operating room and the doctor said, “I can’t operate on you. You’re my son.”
How is that possible?

Q: What occurs once in a minute, twice in a moment and never in one thousand years?

I'll post the answers after you have guessed. Guess in a reply to this post. DON'T USE THE INTERNET PLS. BE FAIR.

q=quarters, d=dimes

q+d=8

.25q+.1d=1.25

Let's set the first equation to equal d.

d=8-q

.25q+.1(8-q)=1.25

Distribute.

.25q+.8-.1q=1.25

Combine Like Terms

.15q+.8=1.25

Subtract .8

.15q=.45

Divide by .15

q=3

Now, let's solve for d in the first equation.

d+3=8

Subtract 3, and you get d=5

So, there are 5 dimes and 3 quarters in Maribel's pocket.

Check: .25(3)+.1(5)=1.25

.75+.5=1.25

1.25=1.25 which is true.