Question 1: Simplify the expression: \((2-3i)(4+2i)\)
For this, we'll use the FOIL method.
2*4=8
8+__+__+__
2*2i=4i
8+4i+__+__
-3i*4=-12i
8+4i-12i+__
-3i*2i=-6i2
(I'm assuming i=sqrt(-1))
8+4i-12i+6=14-8i
Option S is your answer
Question 2: Simplify the expression: \((3x^4+9x^3-7x+15)+(-6x^4-8x^2+5x-3)\)
This is adding like terms.
First, let's start with x^4
3-6=-3
-3x4+9x3-8x2+__+__
There were only one x^3 and x^2 in the expression, so we know that part for sure.
Now, to the x term.
-7+5=-2
-3x4+9x3-8x2-2x+__
Now, to the normal numbers.
15-3=12
Final answer: -3x4+9x3-8x2-2x+12
Hope this helped!