reinout-g

YAY!

Maybe we should ask André to give an extra star for every 1000 posts 

Complex infinity...

Because infinity wasn't complex they made it more complex by defining the complex infinity which is undefined like infinity

$$log_4(x)=\sqrt{log_4(x)}$$

$$(log_4(x))^2 = log_4(x)$$

$$(log_4(x))^2-log_4(x) = 0$$

$$log_4(x)(log_4(x)-1) = 0$$

$$log_4(x) = 0$$ or $$log_4(x) = 1$$

$$x = 1$$ or $$x = 4^1 = 4$$

Sorry for the double solution, but I wanted a variant which also gave $$x=1$$

Reinout 

Look at this question,

it is a very similar question and will probably be of enough help;

Nothing but 1, their greatest common divisor is 1

In prime numers

26 = 2*13

and

99  = 3*3*11

Well, there are 6 articles to choose from of which 4 are a 'succes' (green shirt, green belt, blue pants or green pants) and 2 are a 'fail' (blue shirt, blue hat)

Therefore there is a probability $$P(green or pants) = \frac{4}{6} = \frac{2}{3} \approx 66.66 \%$$ that he picks something green or pants and a probability $$P(notgreenorpants)=\frac{2}{6} = \frac{1}{3} \approx 33.33\%$$ that he doesn't pick something green or a pair of pants.

Reinout