reinout-g

I don't understand what you mean but let me give you some help on how you can write this down properly.

Click on the box 'LaTex Formula', write down \sqrt{} for the sq. root and put everything within the square root between the brackets. Wait for the thing to load and you'll have a brilliantly looking sq. root

(oh and use * for times)

Reinout

Yeah that's not that hard,

150mm = 0.15m

You can imagine that it is a box of which you're trying to find the volume.

The formula for a box is length*width*heigth

You know length*width = 1000

and you know height = 0.15m

So the volume you need is 1000*0.15 = 150 m^3

Reinout

All right, so here's my solution to the problem.

We apply the euclidean algorithm (I'll show you later why)

First we see how many times 19 fits into 49 and we add the remainder

Then we check how many times the remainder fits into 19 and write down a new remainder

Now we check how many times the new remainder fits into the old remainder and we keep on doing this until we have no remainder left.

49 = 19*2+11

19 = 11*1+8

11 = 8*1 + 3

8 = 3*2 + 2

3 = 2*1 + 1

2 = 1*2 + 0

Now we write the one-but-last equation into 1 = 3-2*1

Given the equation above this we can also write 1 = 3-1*(8-3*2).

This gives 1 = 3*3-8

Then again since we know 3 = 11-8*1 from the above equation

This can be rewritten as 1 = 3*(11-8*1)-8 = 3*11-4*8

Basically we keep writing the smallest number as the difference between two larger numbers following the upper equation until we have a difference of a*49-b*19 = 1

Let me put  all the steps underneath each other to make it easier to see

1 = 3-1*2

1 = 3-1*(8-3*2)

1 = 3*3-8

1 = 3*(11-8)-8

1 = 3*11-8*4

1 = 3*11-(19-11*1)*4

1 = 3*11+4*11-19*4

1 = 7*11-19*4

1 = 7*(49-19*2)-19*4

1 = 7*49-19*14-19*4

1 = 7*49-18*19

if

1 = 7*49-18*19

then

900 = 900*7*49-900*18*19

so

900 = 6300*49-16200*19

Now if we substact 19 from 6300 and 49 from 16200 the equation stays the same.

For example

900 = (6300-19)*49-(16200-49)*19

900 = 6281*49-16151*19

We want to substract 49 just 'enough' times to make it negative (so that the equation becomes an addition)

16200/49 = 330.6

So we are going to do it 331 times

then we have

900 = (6300-19*331)-(16200-49*331)*19

900 = 11*49--19*19

900 = 11*49+19*19

Now if we get back to the equation

11+19+L = 100

L = 70

Let's check that in the first equation

50*11+20*19+70 = 1000

So, she sold 11 caviar sandwiches, 19 bologna sandwiches and 70 liverwurst sandwiches

((C,B,L) = (11,19,70))

Reinout 

p.s. it is the only answer

the closest integer answers are

C = 11-19 = -8, B = 19+49 = 68 and L = 100-68+8 = 40

50*-8+20*68+40 = 1000 but C<0

and

C = 11+19 = 30, B = 19-49 = -30 and L = 100-30+30 = 100

50*30+20*-30+100 = 1000 but B<0

Have a look at this question, 

I've done such an equation before... 

Haha number cube. I like that term.

Have a look at this table;

As you can see there are 10 out of 36 possibilities greater than 8.

Therefore the chance is 10/36 = 0.2777777 = 27.77%

Reinout 

If there are 11 girls and 13 boys, there are 11+13 = 24 children in the class.

since 13 of them are boys, the chance of selecting a boy is $$P(Boy) = \frac{13}{24} = 0.5417 = 54.17\%$$

Okay, so here's what happened.

I wrote a 2/3 page answer solving the thing, after which I checked my answers.

My answers were wrong 

Then I used an equation solver to check your equation and it gave me 

$$x_1=0.716$$

$$x_2=6.28$$

Did you by any chance miswrite something in your equation?

Currently you have this;

$$2^{2/x} * 4^{x/6}* ((1/8)^{1/x})^{1/6}=2^2*2^{1/3}$$