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Stu
Username
Stu
Score
1313
Membership
Stats
Questions
73
Answers
292
81 Questions
302 Answers
0
951
1
+1313
Is this image conveying accurately?
is it accurate?
where did the 60 v come from?
do you have to draw on amp leaving battery to be correct? *fig 2.
why when take away the v source, do we leave 28 ohm when it it cannot carry current? is it just that when we cant
read more ..
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Stu
Oct 26, 2014
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2032
7
+1313
help with circuits
can anyone make then selc available to call or skype with to assist me with some cir uit fundementals tonight for an exam in the morning?
LancelotLink
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Stu
Oct 26, 2014
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Mesh/Kirchhoffs theorem.
can someone define the values in the equation one and two stated in the image please.
Alan
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Stu
Oct 7, 2014
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#9
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Bump
Stu
Feb 23, 2014
#2
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0
Bump
Stu
Feb 23, 2014
#7
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+3
What's harder to gain a thorough understanding of while under time constraints: Calculus or Vectors in Engineering?
Stu
Feb 23, 2014
#2
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so the 1/6 is the square of 86 by 36?
Also can't we surd the 86? If yes, how would that work exactly given the 1/6 in front of the 86?
Stu
Feb 21, 2014
#8
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Yeh, I knew it was simple. lol. I even went over this yesterday in a different example to flip the fraction which came to me after posting. Thanks for the reply. lol. Still have to absorb it, enough to remember all, apply as needed and enough to do method in reverse. It's a slow process when it's all new.
Nice wiki link.
Stu
Feb 19, 2014
#5
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solve log
4
(1/4).. What do I do with the fraction in a log situation. How in the instance described do I apply log
a
m
n
= n log
a
m. Oh It should be so easy. Got to work out some of the nuts and bolts I think with this one.
and working this to: 2 log
a
5 + log
a
p
Stu
Feb 19, 2014
#2
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That isn't that clear to me Rom. Also I'm unsure which part of the question you're answering specifically. Though I feel it's conversion process for any log function into a base 10 log. But it seems alien and a bit backwards, though I'm sure it's not.
Specifically, this does not expalin to me how it goes from a log 4 function to a log 10 function, or how to calculate a log 4 function manually, in steps (since I have the problems and the fomulae but not the method) and It does not really explain what is x b and c, where we have one equation, what's what.
logb(x) = logc(x) / logc(b)
so
log10(x) = logc(x) / logc(10)
If you could explain it a bit more thanks.
My interpretation would be logb is log input any base and it will be calculated by log original base by log new base. And what about powers? And how do we solve for powers? What's the step from log 2 or 4 or 7 etc.
Still would like to know the calculation method to manually calculate for example log
4
78. and maybe you can show a little bit of a more difficult log problem and solve to show me also. But I'd like to know the method of working through it specifically and where powers are involved. Ie. what's being Sqrt'ed, multiplied, divided etc to come up with an answer if any one would like to help.
Stu
Feb 18, 2014
#1
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0
I'd neglect to answer this question based on your user name. Please register a better name or take your energy elsewhere.
Stu
Feb 17, 2014
#2
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6 or 6 ones or six units.
Stu
Feb 17, 2014
#1
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Bump~ Title your posts well to find it again in search engine and to help others to do so as well.
Stu
Feb 17, 2014
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