If you mean factorising this is how to do it:
Lets first write the equation:
$$36x^8-16x^4+50x^3$$
What we want to do is to write it in a form that is 'Simpler':
So first what we do is see if there is a HCF (Highest Common Factor) of the Co-efficient.
The Co-efficients have been bolded for you:
$$\mathbf{36}x^8-\mathbf{16}x^4+\mathbf{50}x^3$$
Is there one?
Yes. It is 2.
Lets place that 2 outside of the brackets that we will form to factorise this equation
$$2(18x^8-8x^4+25x^3)$$
Techincally this is correct. But it can be factorised further.
Now we look at the Indicies.
The Indicies is the plural for Index which is the small power in Superscript above $$x$$.
Now the rules for Indicies are slightly different. Multiply is Addition for Indicies and Division is Sutraction for Indicies.
Because it is 'Addition' We only need to find the smallest number with the same pronumeral which is $$x$$
This number is 3.
Lets shift that $$x^3$$ outside the brackets with the 2.
So we would get:
$$2x^3(18x^5-8x+25)$$
That is the answer.
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