Of course, a dice has 6 faces that are all equally likely to occur.
A) Let's make a table that illustrates the probability of just one 6 showing up on one roll:
Possible Events | Meets Condition | Does Not Meet Condition | |
1 | ✘ | ||
2 | ✘ | ||
3 | ✘ | ||
4 | ✘ | ||
5 | ✘ | ||
6 | ✓ | ||
Probability | -------------------- | 1/6 | 5/6 |
As you can see from this table, there is only a 1/6 probability of getting a 6 the first time. What about three times in a row? Multiply the probabilities of all independent events together. Each event has a 1/6 chance.
\(P=(\frac{1}{6})^3=\frac{1}{6}*\frac{1}{6}*\frac{1}{6}=\frac{1}{216}\approx0.46\%\)
Therefore, there is a 1/216 chance in rolling a 6 three times in a row.
B)
We'll use the same method as above. However, these events aren't all the same, so we'll have to calculate the events independently.
Let's do it for rolling a 5
Possible Events | Meets Condition | Does Not Meet Condition | |
1 | ✘ | ||
2 | ✘ | ||
3 | ✘ | ||
4 | ✘ | ||
5 | ✓ | ||
6 | ✘ | ||
Probability | -------------------- | 1/6 | 5/6 |
The probability of rolling a five is alos 1/6. Let's try the next event for seeing the chances of rolling a 1:
Possible Events | Meets Condition | Does Not Meet Condition | |
1 | ✓ | ||
2 | ✘ | ||
3 | ✘ | ||
4 | ✘ | ||
5 | ✘ | ||
6 | ✘ | ||
Probability | -------------------- | 1/6 | 5/6 |
Here, too, there is a 1/6 probability of rolling a 1. Let's find the possibility of rolling an even number:
Possible Events | Meets Condition | Does Not Meet Condition | |
1 | ✘ | ||
2 | ✓ | ||
3 | ✘ | ||
4 | ✓ | ||
5 | ✘ | ||
6 | ✓ | ||
Probability | -------------------- | 3/6=1/2 | 3/6=1/2 |
Now that we have determined the probability of each event occurring. Multiply the probabilities of each event together to get the total probability:
\(\frac{1}{6}*\frac{1}{6}*\frac{1}{2}=\frac{1}{72}\approx1.39\%\)
Therefore, there is a 1/72 chance of rolling a 5, then a 1, and then an even number.
C)
Use the same method as illustrated above.
Let's first find the probability of getting an odd number:
Possible Events | Meets Condition | Does Not Meet Condition | |
1 | ✓ | ||
2 | ✘ | ||
3 | ✓ | ||
4 | ✘ | ||
5 | ✓ | ||
6 | ✘ | ||
Probability | -------------------- | 3/6=1/2 | 3/6=1/2 |
Now, let's find the probability of a number greater than 2:
Possible Events | Meets Condition | Does Not Meet Condition | |
1 | ✘ | ||
2 | ✘ | ||
3 | ✓ | ||
4 | ✓ | ||
5 | ✓ | ||
6 | ✓ | ||
Probability | -------------------- | 4/6=2/3 | 2/6=1/3 |
Finally, the last one, which is rolling a 5:
Possible Events | Meets Condition | Does Not Meet Condition | |
1 | ✘ | ||
2 | ✘ | ||
3 | ✘ | ||
4 | ✘ | ||
5 | ✓ | ||
6 | ✘ | ||
Probability | -------------------- | 1/6 | 5/6 |
Multiply the probabilities
\(\frac{1}{2}*\frac{2}{3}*\frac{1}{6}=\frac{2}{36}=\frac{1}{18}\approx5.56\%\)
YOu're done now!
SImplifying this should be relatively simple.
\(-2i(4-3i)+6i\) | Distribute the -2i into the parentheses |
\(-8i+6i^2+6i\) | Combine the like terms |
\(-2i+6i^2\) | Rearrange the terms so the term with the highest degree is first |
\(6i^2-2i\) | You are done! |
In this equation, your eventual goal is to isolate y. Let's see how to do this:
\(y-1-2y=y+1-3y\) | Simplify both sides of the equation by combining like terms. In this case, the linear terms can be combined to simplify things |
\(-y-1=-2y+1\) | Add y to both sides of the equation. Doing this will have a y that will cancel on the left hand side. |
\(-1=-y+1\) | Subtract 1 from both sides |
\(-2=-y\) | Divide by -1 to get rid of the negative sign on the y. |
\(2=y\) | |
If you are ever pondering about whether or not this answer is correct, plug the answer you got into your equation and see if the statement is true. :
\(y-1-2y=y+1-3y\) | Replace all instances of a y with a 2 |
\(2-1-2*2=2+1-3*2\) | Simplify and see if the statement is true |
\(2-1-4=2+1-6\) | |
\(1-4=3-6\) | |
\(-3=-3\) | Indeed, this is a true statement. |
Therefore, \(y=2\) is the correct and only correct solution for the given equation
Use the trigonometric ratios to find the height of the building:
\(\frac{\tan 53}{1}=\frac{x}{30}\) | The tangent trigonometric ratio compares the opposite angle and the adjacent angle. Cross multiply to isolate x. |
\(30\tan 53ft=x\) | Use a calculator to approximate the height of the building |
\(30 \tan(53)\approx39.8113ft\) | Of course, leave units in your final answer! |
One last note before you go!
Be sure that your calculator is in degree mode when doing this calculation!