math

Thanks x^2 you are absolutely correct :)

But sometimes the letter i is used as the basic unit of the comples (imaginary) number system.

 

If i is the imaginary number then  \(i=\sqrt{-1}\)

 

Then 

 

\(6i^2-2i\\ =6*-1-2i\\ =-6-2i\)

SImplifying this should be relatively simple. 

 

\(-2i(4-3i)+6i\)	Distribute the -2i into the parentheses
\(-8i+6i^2+6i\)	Combine the like terms
\(-2i+6i^2\)	Rearrange the terms so the term with the highest degree is first
\(6i^2-2i\)	You are done!