+0  
 
0
356
2
avatar

-2i(4 - 3i) + 6i

 Jun 7, 2017

Best Answer 

 #2
avatar+95175 
+2

Thanks x^2 you are absolutely correct :)

But sometimes the letter i is used as the basic unit of the comples (imaginary) number system.

 

If i is the imaginary number then  \(i=\sqrt{-1}\)

 

Then 

 

\(6i^2-2i\\ =6*-1-2i\\ =-6-2i\)

.
 Jun 7, 2017
 #1
avatar+2298 
+2

SImplifying this should be relatively simple. 

 

\(-2i(4-3i)+6i\) Distribute the -2i into the parentheses
\(-8i+6i^2+6i\) Combine the like terms
\(-2i+6i^2\) Rearrange the terms so the term with the highest degree is first
\(6i^2-2i\) You are done!
   
   
   
   
   
   
 Jun 7, 2017
 #2
avatar+95175 
+2
Best Answer

Thanks x^2 you are absolutely correct :)

But sometimes the letter i is used as the basic unit of the comples (imaginary) number system.

 

If i is the imaginary number then  \(i=\sqrt{-1}\)

 

Then 

 

\(6i^2-2i\\ =6*-1-2i\\ =-6-2i\)

Melody Jun 7, 2017

20 Online Users

avatar
avatar
avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.