Here's a method to convert any repeating decimal to a fraction.
The first step is to set it equal to a variable; I'll use the standard one, x.
\(7.428571428571...=x\)
Next step is to get only one portion of the repeating portion to the right hand side of the equation. I will demonstrate this:
\(7.428571428571...=x\) | Continue moving the decimal point to the right until you make it to the start of the repeating portion again. |
\(7428571.428571...=1000000x\) | Of course, if you move the decimal place, it the the same as multiplying by 10. We must keep this equation balanced. |
\(\begin{align} 742857.428571&=100000x\\ 7.42857142857...&=x\\ \end{align}\)
Subtract the equations together to get the following:
\(7428564=999999x\)
Divide by the coefficient of x on both sides.
\(x=\frac{7428564}{999999}\)
This is your final answer. I do not believe the numerator and denominator have any common factors.
To solve this problem, we must figure out how much square feet the entire room is. We know the length and the width of the room. Since, this room is rectangular, we can use that information to figure out how much square feet this room covers.
\(8\frac{3}{4}*9\frac{1}{3}\) | First, convert both fractions to improper fractions so that we can multiply them. I will convert each one separately. |
\(8\frac{3}{4}=\frac{4*8+3}{4}=\frac{35}{4}\) | |
\(9\frac{1}{3}=\frac{3*9+1}{3}=\frac{28}{3}\) | Now, let's multiply both together. |
\(\frac{35}{4}*\frac{28}{3}\) | 4 and 28 have a common factor of 4. Doing this simplification makes it easier computationally. |
\(\frac{35}{1}*\frac{7}{3}\) | Now, do the multiplication. One-digit multiplication is simpler than doing 2-digit. |
\(\frac{245}{3}\) | |
We aren't done yet, though! The question is asking how much carpet is remaining after covering the entire floor. This requires the subtraction operator.
\(85-\frac{245}{3}\) | Make 85 a fraction in which it has a denominator of 3. |
\(\frac{85}{1}*\frac{3}{3}=\frac{255}{3}\) | |
\(\frac{255}{3}-\frac{245}{3}\) | Now, we can subtract knowing that we have common denominators. |
\(\frac{10}{3}ft^2\) | And of course, do not forget to include units, if applicable. |
Therefore, after completely covering the \(\left(8\frac{3}{4}\right)^{'} * \left(9\frac{1}{3}\right)^{'}\)rectangular room in carpet, Rodger will have \(\frac{10}{3}ft^2=3\frac{1}{3}ft^2=3.\overline{33}ft^2\) of carpet left.
I understand, I think! I will simplify \(36\div12+5-(4)(6)+(16-8)\).
\(36\div12+5-(4)(6)+(16-8)\) | First, do what is inside of the parentheses. |
\(36\div12+5-4*6+8\) | Let's simplify both the division and multiplication now. |
\(3+5-24+8\) | Now, evaluate from left to right. |
\(8-24+8\) | |
\(-16+8\) | |
\(-8\) | |
It is possible that, after all of this solving, that you have a question. If you do, just ask! I (or any other active member of this forum) will be happy to answer. Don't hesitate.
Thanks for responding quickly! I will evaluate it, to your choice, as the latter one of \(f(7)=\frac{6(x+3)}{11(x+7)}\).
\(f(7)=\frac{6(x+3)}{11(x+7)}\) | First, replace every instance of x with 7, as x=7 by the given information. |
\(\frac{6(7+3)}{11(7+7)}\) | Simplify within the parentheses first. |
\(\frac{6*10}{11*14}\) | Now, simplify both the numerator and the denominator. However, to make it easier computationally, notice how 14 and 10 have a common factor of 2, so we can factor it out, so we don't have to do 11*14, which some have not memorized yet. |
\(\frac{6*5}{11*7}\) | Now, simplify the numerator and denominator. |
\(\frac{30}{77}\) | |
#4
I will evaluate \(6^2+4(17+5)-50-(36-10)\) now
\(6^2+4(17+5)-50-(36-10)\) | First, evaluate inside of the parentheses first to adhere to the order of operations. |
\(6^2+4*22-50-26\) | Do any exponents next, in this case 6^2. |
\(36+4*22-50-26\) | Now, do the multiplication since that is prioritized above addition and subtraction. |
\(36+88-50-26\) | Now, compute from left to right. |
\(124-50-26\) | |
\(74-26\) | |
\(48\) | |
Time to do #2. Now, I will simplify the expression, as I interpret it to be, \(\frac{6*4}{7}+\left(\frac{5}{6}+\frac{1}{3}\right)\):
Of course, the parentheses are unnecessary in this expression as any order of adding is allowed by the associative property of addition. There is also one for multiplication.
\(\frac{6*4}{7}+\frac{5}{6}+\frac{1}{3}\) | Simplify the numerator of the leftmost fraction. |
\(\frac{24}{7}+\frac{5}{6}+\frac{1}{3}\) | The LCD in this case is 42, so convert all fractions to have this common denominator. |
\(\frac{24}{7}*\frac{6}{6}=\frac{20*6+4*6}{42}=\frac{144}{42}\) | |
\(\frac{5}{6}*\frac{7}{7}=\frac{35}{42}\) | |
\(\frac{1}{3}*\frac{14}{14}=\frac{14}{42}\) | Now, add the fractions together. |
\(\frac{144}{42}+\frac{35}{42}+\frac{14}{42}=\frac{193}{42}\) | |
I'll solve each one in a different comment.
#1
Simplify the expression \(\frac{5}{9}+\frac{2}{3}+\frac{1}{4}+5\).
\(\frac{5}{9}+\frac{2}{3}+\frac{1}{4}+5\) | Get every fraction in a form such that all the fractions have a common denominator. The LCD of 9,3, and 4 is 36. Therefore, out goal is to convert every fraction that it has a denominator of 36. |
\(\frac{5}{9}*\frac{4}{4}=\frac{20}{36}\) | |
\(\frac{2}{3}*\frac{12}{12}=\frac{24}{36}\) | |
\(\frac{1}{4}*\frac{9}{9}=\frac{9}{36}\) | Reinsert all of these fractions into the orginal expression. |
\(\frac{20}{36}+\frac{24}{36}+\frac{9}{36}+5\) | Add the fractions together. |
\(5\frac{53}{36}\) | Now, convert this mixed number into an improper fraction. |
\(5\frac{53}{36}=\frac{36*5+53}{36}=\frac{233}{36}\) | |