In the problem it said

Let F(x) be the real-valued function defined for all real x except for x=1 and x=2

turn this into: 7x^2 + 8x - h = 0

using the quadratic formula to find the solutions:\({-8 \pm \sqrt{64+28h} \over 14}\)

this means that \(\sqrt{64+28h}\) = 0

h = \(-\)\(16\over 7\)

The ratio can be expressed as 9x:2x:5x. we get the equation:

\(9x*2+2x*5+5x*10-9*\frac{4}{9}x*2-50=300\)

Simplifying it we get:

\(18x+10x+50x-8x=350\)

\(70x=350\)

Soving it we get x=5. This means that there are \(5*5=\boxed{25}\) $10 notes

a=3 b=2

you can see the answer here: https://web2.0calc.com/questions/how-many-ways-are-there-to-put-4-balls-in-3-boxes_2

read the one with the most thumbs ups

the total of the 10 numbers is: 10(85)=850

subtracting 70 and 78 gives 850-70-78=702

dividing by 8 gives: 87.75

since there are 9 numbers and choose 3 to be in so we can do 9!/6!=504 but some numbers are repeated in the list which are 5 and 6. 5 is repeated three times and 6 is reapeated twice so we divide by 2! and 3!

504/2/6=42

100^2-100+201=10101

101^2-101+201=10301

10301 is prime so the gcd is 1

for \(\LaTeX\)you can't copy and paste you have to type it in your self

G+16=24-3/4*G

G=8-3/4*G

7/4*G=8

G=(32)/7

The one on this website or a different one? For web2.0calc just do (numerator÷denominator) i think

x+y=13

2x+6y=50

x+3y=25

subsitution gives:

2y=12

y=6 x=7