Let 7x^2 + 8x = h. What value of h will give us exactly one solution for x?
turn this into: 7x^2 + 8x - h = 0
using the quadratic formula to find the solutions:\({-8 \pm \sqrt{64+28h} \over 14}\)
this means that \(\sqrt{64+28h}\) = 0
h = \(-\)\(16\over 7\)
