(1) floor [ (2 - 3x) / ( x + 5) ]
Note f(1) = -1 and f(1000) = -3
f(1) = -1
f(2) = -1
f(3) = -1
f(4) = - 2
Now, we need to find out where the function = exactly -2
Solving this
[ (2 - 3x) / ( x + 5) ] = -2, we have x = 12
So.....from f(4) to f(12), the function takes on a floor value of -2 for each successive integer value of x
And from f(13) to f(1000) the function takes on a floor value of -3 for each successive integer value of x
So
f(1) + f(2) + f(3) + ... + f(999) + f(1000) =
3(-1) + 9(-2) + 988(-3) =
-2985
