2x-3+3x-2=90
\(2x-3+3x=90\)
add 3 to both sides
\(2x+3x=90+3\)
collect terms
\(5x=93\)
divide by 5
\(x=\frac{93}{5}\)
ta dah!
oh okay - derp moment there
just put \(\frac{5}{95}\)instead of \(\frac{3}{95}\)
which cancels to \(\frac{1}{19}\)
2x-3+3x-2=90 combine like terms on the left
5x - 5 = 90 add 5 to each sides
5x = 95 divide both sides by 5
x = 19
