+0  
 
0
440
2
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(x+2)^2+y^2

 Sep 22, 2016
 #1
avatar+129840 
0

(x+2)^2+y^2

 

The center would be (-2, 0)

 

Unfortunately, we need an equation to determine the radius  [ i.e., an equal sign and a number appended to what you have]

 

 

 

 

cool cool cool

 Sep 22, 2016

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