CPhill

1 foot = 12 inches.....so...

3.5 ft  * 12    =

(3 + 1/2) * 12  =

3 * 12   +   (1/2) * 12  =

36    +   6 =

42 inches

If I didn't have to "verify" my answers, it would be just fine......hectictar indicates that we can go back and edit our old posts......I like that.....!!!!

Note....any number of the form  abcdabcd   can be written as

abcd *  10000  +  abcd   =

adcd ( 10000 + 1) =

abcd (10001)

So.....10001 is the greatest common divisor for any number of this form

 √32  = √ (16 *2)  = √16 * √2   =  4√2

 √44  = √{4 * 11} = √4*√11 = 2√11

 √90 = √[9 * 10] = √9 *√10 = 3√10

x^7 =  250000     take the 7th root of both sides

x = (250000)^(1/7)  ≈ 5.903836027749965

r = sqrt [ (-6)^2 + (1)^2 ]    =  sqrt (37)

To find theta, we have

atan ( 1/ -6)   = -0.165148677415

However.....this point lies in the second quadrant so we must add pi radians to it.....and we have

-0.165148677415  + pi   ≈ 2.9764    rads

So   (-6, 1)  rectangular  =

(r, theta)   = ( sqrt (37),  2.9764)

3 + 1/2  =

7/2 =

3.5

650/1430 = 320/x   cross-multiply

650x   =  1430 * 320        divide both sides by 650

x =  ( 1430 * 320 ) / 650   =  704

u = < - 2, 8 >

v = < -7, - 9 >

cos (theta)   =   u (dot) v / [ ll u ll * ll v ll ]

u (dot) v   =   14 - 72  =   -58

ll u ll  =   sqrt [ (-2)^2 + (8)^2 ]  =  sqrt (68)

ll v ll   =   sqrt [ (-7)^2 + (-9)^2 ]   =  sqrt [ 49 + 81]   =  sqrt (130)

cos (theta)   =   -58 / [ sqrt (68) * sqrt (130) ]

arcos  [ -58 / [ sqrt (68) * sqrt (130) ] ]   = theta   ≈ 128.0888°

Here is a graph that shows this, Veteran :

u =  < -19. - 13 >

v = < 6 , -13 >

u + v    =   < -19 + 6, -13 + - 13 >    =  < -13, -26 >

ll u + v ll   =    sqrt [ (-13)^2 + (-26)^2 ]   ≈ 29.0689