Alan

@Dragonlance:

In real life there might well be occasions when it is ok to assume there is no effective difference between temperatures that are only half a degree apart.  However, there was no indication in civonamzuk's question that this was the case here. The fact that he quoted a temperature to 2 decimal places suggested that the decimal places were significant.  Taken with the fact that 0°C is 273.15K, then 233.16K is (very slightly) higher than the other two temperatures.  (273.16K is an important temperature in science - it is the temperature of the triple point of water - that is where water, steam and ice exist in equilibrium with each other).

I'm pleased to hear you want to do well in school.  I wish you all the best.

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25% of $28 is 1/4 of $28, which is $7

if this is his profit and he paid $28 for it, then he must have sold it for $28 + $7 = $35

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(Melody beat me to it)

I assume the "8" in T8 and M8 means use 8 panels.  If so then:

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Careful with units Eloise.  cm*cm are cm² so your third line should be 12283 cm²

This is 1.2283 m²

I'll still give you points for trying though

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Get this in the form (x - xc)² + (y - yc)² = r²

First look at the x-terms

x² + 3x can be written as (x + 3/2)² - 9/4  = (x - -3/2)² - 9/4  giving xc = -3/2

Now look at the y-terms

y² can be written as (y - 0)² giving yc = 0

(xc, yc) = (-3/2, 0)

So the original equation can be written as (x + 3/2)² - 9/4 + (y - 0)² - 17 = 0

or (x + 3/2)² + (y - 0)² = 17 +9/4

or (x + 3/2)² + (y - 0)² = 77/4

so r² = 77/4

r = (√77)/2

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The equation will be in the form (x - xc)² + (y - yc)² = r² where (xc, yc) are the coordinates of the centre (in this case xc = -5 and yc = -10) and r is the radius, obtained here from r² = (-11 - -5)² + (-9 - -10)² or r² = 37, so:

(x + 5)² + (y + 10)² = 37

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What makes you think it isn't?!!!

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$$8\times(-\frac{1}{2})^2\rightarrow8\times \frac{1}{4}\rightarrow 2$$

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In general log_b(x) = n means that x = bⁿ, where b is the base.

In your case, if b = 10, then x = 10^-0.596 

$${\mathtt{x}} = {{\mathtt{10}}}^{\left(-{\mathtt{0.596}}\right)} \Rightarrow {\mathtt{x}} = {\mathtt{0.253\: \!512\: \!863\: \!049\: \!790\: \!8}}$$

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I don't agree with Dragonlance here; I agree with civonamzuk's original reply.  I see no reason (in science or mathematics) to assume that temperatures within half a degree of each other should be considered the same in general!

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