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Holt read 1/5 of a book on Monday, another 28 pages of the book on Tuesday and 7/12 of the remaining pages on Wednesday. There were 25 pages left unread. How many pages were there in the book?

 Oct 16, 2021
 #1
avatar+294 
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\([math]\left(x-\frac{1}{5}x-28\right)\left(1-\frac{7}{12}\right)=25\\ \left(\frac{4}{5}x- 28\right)\frac{5}{12}=25\\ \left(\frac{4}{5}x-28\right)=60\\ \frac{4}{5}x=88\\ x=110[/math]\)
Holt read 110 pages

 Oct 16, 2021
 #2
avatar+1607 
0

x - [x/5 + 28 + 7/12(x - x/5 -28)] = 25

 

x = 110

 Oct 16, 2021
 #3
avatar+80 
0

Reading of 7/12 of the remaining pages on Wednesday means 5/12 of the remaining pages=25 pages

The remaining pages=25*12/5= 60 pages

Read 28 pages of the book on Tuesday=60+28=88

As read 1/5 of a book on Monday, 88 pages constitutes 4/5 of the book

Number of pages in the book=88/(4/5)=88*5/4=110 number

 Oct 16, 2021

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