The average number of Peter's stickers and Jordan's stickers is 924. Peter has 232 more stickers than Jordan. Albert has 172 stickers more than Peter. What fraction of Albert's stickers are Jordan's stickers? Write your answer in its simpliest form
+37146 p + j = 924 (2) = 1848
p = j + 232 so p = 1040 and j = 808
a = p + 172 = 1212
j / a = 808 / 1212 = 2/3
+313 Let,
a = Peter's sticker
b = Jordan's sticker
c = Albert's sticker
Given:
1) \({a + b \over 2} = 924\) (average number of Peter's & Jordan's stickers)
a + b = 2(924)
a + b = 1848 (1)
2)
a = b + 232 => a - b = 232 (232)
3)
c = a + 172 (3)
Solve for a using eq. (1) & (2), eliminate b
a + b = 1848
+ a - b = 232
2a = 2080
2a/2 = 2080/2
a = 1040
Find b. Find c.
a + b = 1848 C = a + 172
b = 1848 - a = 1040 + 172
= 1848 - 1040 C = 1212
b = 808
So,
\( {Jordan’s stickers \over Albert’s stickers} = {b \over c} = {808 \over 1212}\)
= 0.6666. . .
Change 0.6666... to fraction.
x = 0.6666 . . .
10x = 6.6666 . . .
- x = 0.6666 . . .
9x = 6
x = 6/9 = 2/3
Therefore,
Jordan's stickers is 2/3 of Albert's stickers.
2/3 * 1212 = 808 ✓
