https://en.wikipedia.org/wiki/Chinese_remainder_theorem

Learn it first

May I ask where you got this? And please SEARCH YOUR PRBLEM BEFORE ASKING FOR HELP

We can use the circle equation:\((x-h)^2+(y-k)^2=r^2\),\(h=\)x of center,\(k=\)y of the center

so \(x^2-2x+y^2=24\) Is now more clearer because if \((h=-1,k=0),(x-1)^2+(y)^2=5^2\)simplified is:

The middle:\((-1,0)\), the raidius \(r=5\)

Nice Guest, very good explanation!

Interesting, because \(x-2=|2x-1|\) , so:\(x\ge0\) Can you continue?

Yes my bad double counting is about different ways to count a set.

Can you explain how you now? Or your cheating on homework?

I'm sorry but this is insane how you can't do simple calculations.

Ya, i just joined but the small things matter to.

here: https://web2.0calc.com/questions/perimeter_13

No problem, thanks!

LaTeX version:\(3x-2x+5-6=9+t+x+7x-8\)So then we simplify it:\(-t=8x+2\) I think you can do the rest.

PS: if you need help tell me

We can try solving this by canceling a variable so \(2(3x-5y)=-2(11), 5(7x+2y)=5(-12)\)then:\(35x+10y+(6x-10y)=-60+(-22)\)we simplify it into \(41x=-82,(x,y)=(-2,1)\)

Do you understand?