Learn it first
May I ask where you got this? And please SEARCH YOUR PRBLEM BEFORE ASKING FOR HELP
We can use the circle equation:\((x-h)^2+(y-k)^2=r^2\),\(h=\)x of center,\(k=\)y of the center
so \(x^2-2x+y^2=24\) Is now more clearer because if \((h=-1,k=0),(x-1)^2+(y)^2=5^2\)simplified is:
The middle:\((-1,0)\), the raidius \(r=5\)
Nice Guest, very good explanation!
Interesting, because \(x-2=|2x-1|\) , so:\(x\ge0\) Can you continue?
Yes my bad double counting is about different ways to count a set.
Can you explain how you now? Or your cheating on homework?
I'm sorry but this is insane how you can't do simple calculations.
Ya, i just joined but the small things matter to.
No problem, thanks!
LaTeX version:\(3x-2x+5-6=9+t+x+7x-8\)So then we simplify it:\(-t=8x+2\) I think you can do the rest.
PS: if you need help tell me
We can try solving this by canceling a variable so \(2(3x-5y)=-2(11), 5(7x+2y)=5(-12)\)then:\(35x+10y+(6x-10y)=-60+(-22)\)we simplify it into \(41x=-82,(x,y)=(-2,1)\)
Do you understand?