If tan−1x+tan−1y=π4, then compute xy+x+y.
xy + x + y = sqrt(2).
that's wrong
Can you explain how you now? Or your cheating on homework?
arctan x + arctan y = pi / 4
This will be true when either
x = 0 and y = 1
or
x = 1 and y = 0
So
xy + x + y = 1
Using the trig identity
tan(A+B)=tanA+tanB1−tanAtanB,
tan(tan−1x+tan−1y)=tan(π/4),(x+y)/(1−xy)=1,x+y=1−xy,x+y+xy=1.