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How many positive integers N from 1 to 5000 satisfy the congruence N = 11 (mod 131)?

 Jul 25, 2022
 #1
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https://en.wikipedia.org/wiki/Chinese_remainder_theorem
 Jul 26, 2022
 #2
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1 = 11
2 = 142
3 = 273
4 = 404
5 = 535
6 = 666
7 = 797
8 = 928
9 = 1059
10 = 1190
11 = 1321
12 = 1452
13 = 1583
14 = 1714
15 = 1845
16 = 1976
17 = 2107
18 = 2238
19 = 2369
20 = 2500
21 = 2631
22 = 2762
23 = 2893
24 = 3024
25 = 3155
26 = 3286
27 = 3417
28 = 3548
29 = 3679
30 = 3810
31 = 3941
32 = 4072
33 = 4203
34 = 4334
35 = 4465
36 = 4596
37 = 4727
38 = 4858
39 = 4989
 

 Jul 26, 2022

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