So can a imaginary number be in a graph like:√−1√−3 Since the i can cancel out
i√1i√3=1√3 which is a real number.
So, this number can be represented on a real number line. (No need for complex plane (argand diagram).)
Yes, we first "simplify" the number then we put it.
And the number is not imaginary; it is real.
That's very interesting! I know another strange fact that i^i is even real!
i = e^{pi/2i}
eπi/2⋅eπi/2 = eπi2/2
The i^2 cancels out as negative and we see that e−π/2 = i ^i which is actually real!
Cool, isn't it! :)