BuilderBoi

Count it by shape:

length x width

1 x 1: 12 

1 x 2: 9

1 x 3: 6

1 x 4: 3

2 x 1: 8

2 x 2: 6

2 x 3: 4

2 x 4: 2

3 x 1: 4

3 x 2: 3

3 x 3: 2

3 x 4: 1

Add everything up, and you get 60.

https://web2.0calc.com/questions/math-problem_32546. CPhill answers this by using PIck's Theorem

\(1 \over 39\) is equal to \(0.0\overline{256410}\)

Digits 2, 8, and 14 are all equal to 2. By dividing, the 288th digit is 2. This means that the 291st digit is 4.

By doing \(7 \over cos{45}\), we find the the hypotenuse of the triangle is 9.9 meters long, meaning that the ladder is 9.9 meters long.

By using the Pytahgorean's theroem, \(9.9^2=7^2+x^2\), we find that the vertical height is \(7\) meters

Plug it in to a calculator, and you get \(11.8780382733 \)

\(2^{10} = 2^{10}\)

\(4^{20} = 2^{2^{20}} = 2^{40}\)

\(8^{40} = 2^{2^{2^{40}}} = 2^{160}\)

\(2^{10} * 2^{40} * 2^{160} = 2^{210}\)

So... \(n = 210\)

I think it was easier than the 2020 AMC 8

Two odds always add up to an even, and an even number raised to any power will aways be even. Thus, your answer is 0.

\( \sqrt{60x} = \sqrt{4} * \sqrt{15x} = 2\sqrt{15x}\) 

\(\sqrt{12x} = \sqrt{4} * \sqrt{3x} = 2\sqrt{3x}\)

\(\sqrt{63x} = \sqrt{9} * \sqrt{7x} = 3\sqrt{7x}\)

\(\sqrt{42x} = \sqrt{42x}\)

Now, multiply all the radicals and you get \(252x^2 \sqrt 30\).

I think...

The answer is 30, and it can be found here: https://web2.0calc.com/questions/halp_104