Find the 291st digit past the decimal point in the expansion of \(\frac{1}{39}\)
\(1 \over 39\) is equal to \(0.0\overline{256410}\)
Digits 2, 8, and 14 are all equal to 2. By dividing, the 288th digit is 2. This means that the 291st digit is 4.
1/39 ==0.025641 025641 025641 025641 025641
Since the fraction has a "period" of 6, or repeating the same 6 digits, therefore the 291st digit should be:
291 mod 6==3, or the 3rd digit from the decimal point, or 5.