What is the value of n if 2^10 * 4^20 * 8^40 = 2^n?
\(2^{10} = 2^{10}\)
\(4^{20} = 2^{2^{20}} = 2^{40}\)
\(8^{40} = 2^{2^{2^{40}}} = 2^{160}\)
\(2^{10} * 2^{40} * 2^{160} = 2^{210}\)
So... \(n = 210\)
I agree with Bs answer until 840 = (23)40 = 120
+2668 
