CalculatorUser

Yes I did

^{Using your fingers, you can count STARTING with your thumb, and counting to your little finger, then ending back on your index finger. You just counted 8 times.}

Based on your statement, the quote above is correct.

Prime factorize 200,000

\(2^6*5^5\)

20! is pretty much already factored for you.

For visualization, we have 20 * 19 * 18 * 17 * 16 * 15 * 14 * 13 * 12 * 11 * 10 * 9 * 8  * 7 * 6 * 5 * 4 * 3 * 2 * 1

Since we have this, \(2^6*5^5\), we try to find the maximum number of 2s and 5s from 20! that can fit into the prime factorization.

We easily have six 2s, and we only have four 5s. 

So we evaluate \(2^6 * 5^4\), and get the answer.

I will leave that up to you.

There are 2015 counts.

Using your fingers, you can count STARTING with your thumb, and counting to your little finger, then ending back on your index finger. You just counted 8 times.

The next count will start a new sequence on your thumb beginning with 9.

So each time we start a new sequence, the counts increase by 8, with the next count being the thumb.

So we can divide 2015 by 8 and find the remainder through long division.

We find that the remainder is 7.

So all we need to do is count from 1 - 7 starting with your thumb, and work your way to your little finger and back to your thumb again.

I can leave that up to you. (It should be easy to count your fingers)

If you want to check, Ronaldo should be the answer.

These are the two points, (-1,3) and (7,3). We can count the distance, which is 8.

(-1,y), (7,y)

they must be along x = -1 nad x = 7.

Since we know the area is 72 units, and we know one side of the rectange is 8, then we can figure out the other side. 72 / 8 = 9

So we add 9 (because y must be positive) to both known coordinates (-1,3) and (7,3) to find y.

3 + 9 = 12

3 + 9 = 12

y must be 12.

Yeah I always have a time weakness. I can basically solve any problem on the AMC 8 if I had time....

Thank you guys for the support though

Are parrelel lines given?

This is a formula that he uses \(A=rs\)

s = semi-perimeter

A = area

r = inradius

Using his method (heron's formula) we can find the value of A.

Using the given info on the triangles side, we can find the semi-perimeter by finding the perimeter and dividing by 2.

Then with that info, we plug it into the formula and solve for R.

sure, i am quite triggered at failing the AMC 8 , but Guest, you really should stop being a garbage, sub-human, lower life form.

no one has use for you in the world. you potatoes who cheat homework, but you end up failing the EASIEST thing to do. CHEAT!

You use our answers without any understanding on how we got it, then you blame us for getting it wrong, when you don't take the measly 5-10 minutes to understand it.

he is the same guest that posts homework questions.

Apparently my answer was wrong, but he doesn't know why because he didn't take time to understand my method, and simply plugged in the answer I got.

Then he gets mad at us for giving wrong answers, and that he didnt get full points on his "homework". 

So basically he is this greedy jerk that blames you for his own problems